On Thu, 17 May 2018, 18:55 Ned Batchelder, <n...@nedbatchelder.com> wrote:
> On 5/17/18 4:23 AM, Abdur-Rahmaan Janhangeer wrote: > > if then a more convenient way might be found to naturally remove and > return the list > > maybe it was not included as one might want to remove the list only > > x = [1] > x.remove(1) > > as opposed to > > x = [1] > x.remove(1) > new_list = x > > i was looking for like > > x = [1] > x.remove(1).return() > > > I don't understand what this would return? x? You already have x. Is it > meant to make a copy? x has been mutated, so I don't understand the benefit > of making a copy of the 1-less x. Can you elaborate on the problem you are > trying to solve? > > --Ned. > > assignment to another var > > -- https://mail.python.org/mailman/listinfo/python-list
