On 2018-05-17 11:26 AM, Abdur-Rahmaan Janhangeer wrote: > I don't understand what this would return? x? You already have x. Is > it meant to make a copy? x has been mutated, so I don't understand the > benefit of making a copy of the 1-less x. Can you elaborate on the > problem you are trying to solve? > > --Ned. > > > assignment to another var >
Though I don’t know what the OP was specifically looking for I could see a benefit to returning the item deleted. So, lets take as an example I have an object like: class ListItem(object): def __init__(self, key, data): self.key = key self.data = data def __eq__(other): return other == self.key and I do something like: i1 = ListItem('hello', 'foobar') l2 = ListItem('goodby', 'snafu') l = [i1, i2] So, lets say I have a need where I want to do something like a remove, but I also want to be able to get the .data variable from the object I am removing, it would be nice to be able to simply do x = l.remove('hello') print(x.data) Yes, I could do a index/pop to get this, or I could keep a separate dict of the objects as well for lookups, or a number of other techniques, but it would be easier to simply get it back during the remove(). Dan Strohl -- https://mail.python.org/mailman/listinfo/python-list