On Wed, 29 Jun 2011 16:01:38 +0200 Floris van Manen <v...@klankschap.nl> wrote:
Hello, > this doesn't > if i call the function it will return a (random?) identical value for > all stored lambda functions. > > def rewrite( d ): > for key in d: > for k in d[key]['next']: > c = float(d[key]['next'][k]['prob']) > d[key]['next'][k]['prob'] = lambda : c > return d > > > There is most likely a reason to it. > Can someone explain me what that reason is ? > c refer to only one variable, which scope is the function rewrite. lambda here create a closure that return the value of this unique variable, that will have as value the one computed in the last iteration of your loop (that's not random). Regards, Sylvain, -- Sylvain Viollon -- Infrae t +31 10 243 7051 -- http://infrae.com Hoevestraat 10 3033GC Rotterdam -- The Netherlands _______________________________________________ Python-nl mailing list Python-nl@python.org http://mail.python.org/mailman/listinfo/python-nl
