On 06/29/2011 04:30 PM, Sylvain Viollon wrote:
On Wed, 29 Jun 2011 16:01:38 +0200
Floris van Manen<v...@klankschap.nl> wrote:
Hello,
this doesn't
if i call the function it will return a (random?) identical value for
all stored lambda functions.
def rewrite( d ):
for key in d:
for k in d[key]['next']:
c = float(d[key]['next'][k]['prob'])
d[key]['next'][k]['prob'] = lambda : c
return d
There is most likely a reason to it.
Can someone explain me what that reason is ?
c refer to only one variable, which scope is the function rewrite.
lambda here create a closure that return the value of this unique
variable, that will have as value the one computed in the last
iteration of your loop (that's not random).
(zullen we python-nl gewoon in het nederlands houden?)
Als workaround kan je dit herschrijven als "lambda x=c: x"
Wichert.
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