Yeah,
My first post missed an essential statement, which unfortunaetly, was the
core aspect of the function, the sort part of the outputed list.
I replied with the corrected version (I set it in bold but I don't know if
everyone sees it in bold), and it then works as expected
def sortByHierarchy(dagList):
# we'll use '@' as it can't never be found in maya node names
sortedByHierarchy = []
for elem in dagList:
depth = elem.count('|')
sortedByHierarchy.append (str(depth) + "@" + elem)
*
*
* * # this was the essential part of the function
* sortedByHierarchy.sort() *
for i in range(sortedByHierarchy.__len__()):
sortedByHierarchy[i] = sortedByHierarchy[i].split('@')[1]
return sortedByHierarchy
dagList = ['|a|b|c', '|a', '|a|b', '|a']
print sortByHierarchy(dagList)
# ['|a', '|a', '|a|b', '|a|b|c']
Anyway, it's useless to say that your version is MUCH more sexy, and after
reading python doc, MUCH more efficient on big lists.
Nicolas
2012/8/24 Justin Israel <[email protected]>
> Example:
>
> dagList = ['|a|b|c', '|a', '|a|b', '|a']
>
> print sortByHierarchy(dagList)
> # ['|a|b|c', '|a', '|a|b', '|a']
>
>
> On Fri, Aug 24, 2012 at 10:37 AM, Justin Israel <[email protected]>
> wrote:
> > Haha, no don't get me wrong. I am totally NOT making a statement that
> > it is lame. I was saying that I don't see where the sort aspect is
> > occurring in your function. All i see is that you append them to the
> > list and then go back over that same list and strip away the bit you
> > put in front again. How does it sort?
> >
> >
> > On Fri, Aug 24, 2012 at 10:33 AM, Nicolas Combecave
> > <[email protected]> wrote:
> >> It does the same as yours but it's okay to say it's lame, obfuscated
> and not
> >> leveraging python power ^^
> >>
> >>
> >> 2012/8/24 Justin Israel <[email protected]>
> >>>
> >>> Well ya, but in your code it wasn't sorting at all. What was it trying
> >>> to do actually?
> >>>
> >>> From a python interp you can do:
> >>> >>> help([].sort)
> >>> sort(...)
> >>> L.sort(cmp=None, key=None, reverse=False) -- stable sort *IN
> PLACE*;
> >>> cmp(x, y) -> -1, 0, 1
> >>>
> >>>
> >>>
> >>> On Fri, Aug 24, 2012 at 10:21 AM, Nicolas Combecave
> >>> <[email protected]> wrote:
> >>> > Actually, looking at the python doc for the list.sort() method, it
> >>> > doesn't
> >>> > mention optional arguments...
> >>> > http://docs.python.org/tutorial/datastructures.html
> >>> >
> >>> > I've had to search in here to find the info:
> >>> > http://docs.python.org/library/stdtypes.html#mutable-sequence-types
> >>> >
> >>> >
> >>> > 2012/8/24 Nicolas Combecave <[email protected]>
> >>> >>
> >>> >> Damn, your version is QUITE shorter!
> >>> >>
> >>> >> As my python is very weak, I tried to do a conversion of how I'd do
> it
> >>> >> in
> >>> >> mel!
> >>> >> I sure do need to deepen my python seriously...
> >>> >> Although I don't fully understand the lambda usage, I sure will look
> >>> >> into
> >>> >> it right now ^^
> >>> >>
> >>> >> So, about the (lame and lenghty) function I sent before, that was
> doing
> >>> >> nothing, it's because in the process of cleaning for pasting into
> >>> >> gmail, I
> >>> >> forgot the sort command...
> >>> >>
> >>> >> It should have been like this...
> >>> >>
> >>> >> def sortByHierarchy(dagList):
> >>> >> # we'll use '@' as it can't never be found in maya node names
> >>> >>
> >>> >> sortedByHierarchy = []
> >>> >>
> >>> >> for elem in dagList:
> >>> >> depth = elem.count('|')
> >>> >> sortedByHierarchy.append (str(depth) + "@" + elem)
> >>> >>
> >>> >> sortedByHierarchy.sort()
> >>> >>
> >>> >> for i in range(sortedByHierarchy.__len__()):
> >>> >> sortedByHierarchy[i] = sortedByHierarchy[i].split('@')[1]
> >>> >>
> >>> >> return sortedByHierarchy
> >>> >>
> >>> >>
> >>> >> The idea was to prefix each long name with it's depth info, sort
> that,
> >>> >> and
> >>> >> strip back this depth info to return a proper list...
> >>> >>
> >>> >> Nicolas
> >>> >>
> >>> >>
> >>> >>
> >>> >> 2012/8/24 Justin Israel <[email protected]>
> >>> >>>
> >>> >>> Maybe I am missing something, but it doesn't seem like the
> >>> >>> sortByHierarchy() function is doing anything.
> >>> >>> It takes in a list, then loops over it, creating a new list with
> the
> >>> >>> depth count + @ + name. Then it just loops back over the new list,
> and
> >>> >>> replaces it with the name again. But no sorting is happening at
> all.
> >>> >>>
> >>> >>> If that function is supposed to simply sort by the depth value,
> >>> >>> couldn't
> >>> >>> you just do this?
> >>> >>>
> >>> >>> dagList.sort(key=lambda x: x.count('|'))
> >>> >>> # dagList.sort(key=lambda x: x.count('|'), reverse=True)
> >>> >>>
> >>> >>> What is the logic of concatenating the depth + @ + name?
> >>> >>>
> >>> >>>
> >>> >>> On Fri, Aug 24, 2012 at 5:54 AM, Nicolas Combecave
> >>> >>> <[email protected]> wrote:
> >>> >>>>
> >>> >>>> I've tested this and it seems to work as you need:
> >>> >>>>
> >>> >>>> import maya.cmds as cmds
> >>> >>>> import random
> >>> >>>>
> >>> >>>> # CREATING RANDOM LOCATORS AND JOINTS TO TEST SNAPPING HIERARCHIES
> >>> >>>> max = 10
> >>> >>>> prevLoc = None
> >>> >>>> prevJoint = None
> >>> >>>>
> >>> >>>> for i in range(max):
> >>> >>>>
> >>> >>>> loc = cmds.spaceLocator(name = "Gizmo_"+str(i))
> >>> >>>> cmds.xform(worldSpace = True, t = [random.random()*10,
> >>> >>>> random.random()*10, random.random()*10])
> >>> >>>> cmds.select(cl = True)
> >>> >>>> joint = cmds.joint(name = "joint_"+str(i), position =
> >>> >>>> [random.random()*10, random.random()*10, random.random()*10])
> >>> >>>>
> >>> >>>> if prevLoc != None:
> >>> >>>> cmds.parent (loc[0], prevLoc[0])
> >>> >>>> if prevJoint != None:
> >>> >>>> cmds.parent (joint, prevJoint)
> >>> >>>>
> >>> >>>> prevLoc = loc
> >>> >>>> prevJoint = joint
> >>> >>>>
> >>> >>>> # HERE YOU CAN REPARENT SOME LOCATORS AND JOINTS IN THE SAME WAY
> IN
> >>> >>>> ORDER TO TEST HIERARCHIES WITH BRANCHES
> >>> >>>>
> >>> >>>> # NOW SNAPPING JOINTS HIEARCHY TO LOCATORS HIERARCHY
> >>> >>>> # WE ASSUME YOU DON'T HAVE DUPLICATE SHORT NAMES IN JOINTS
> HIERARCHY
> >>> >>>> liste = cmds.ls('Gizmo_*', type = "transform", dag = True, l =
> True)
> >>> >>>>
> >>> >>>> for gizmo in liste:
> >>> >>>> gizmo_id = gizmo.split('|')[-1].split('_')[-1]
> >>> >>>> joint_id = "joint_" + gizmo_id
> >>> >>>> gizmoPos = cmds.xform(gizmo, q = True, worldSpace = True, t =
> >>> >>>> True)
> >>> >>>> cmds.xform(joint_id, worldSpace= True, absolute = True, t =
> >>> >>>> (gizmoPos[0],gizmoPos[1],gizmoPos[2]))
> >>> >>>>
> >>> >>>>
> >>> >>>>
> >>> >>>> Anyway, it's always a good thing to have a little utility
> function to
> >>> >>>> order list by hierarchy
> >>> >>>> Here is one quickly hacked:
> >>> >>>>
> >>> >>>> def sortByHierarchy(dagList):
> >>> >>>> # we'll use '@' as it can't never be found in maya node names
> >>> >>>>
> >>> >>>> sortedByHierarchy = []
> >>> >>>>
> >>> >>>> for elem in dagList:
> >>> >>>> depth = elem.count('|')
> >>> >>>> sortedByHierarchy.append (str(depth) + "@" + elem)
> >>> >>>> for i in range(sortedByHierarchy.__len__()):
> >>> >>>> sortedByHierarchy[i] = sortedByHierarchy[i].split('@')[1]
> >>> >>>>
> >>> >>>> return sortedByHierarchy
> >>> >>>>
> >>> >>>> print sortByHierarchy(liste)
> >>> >>>>
> >>> >>>> Nicolas
> >>> >>>>
> >>> >>>> --
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> >>> >>
> >>> >>
> >>> >
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> >>
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