You can use a single regular expression, with capture groups:
In [1]: import re
In [2]: path = r'P:\foo\bar\biz\scene\ch01\seq001\s0090\anim\foo\bar\biz'
In [3]: match = re.search(r'(ch\d{2})\\(seq\d{3})\\(s\d{4})', path)
In [4]: if match:
...: print match.groups()
...:
('ch01', 'seq001', 's0090')
In [5]: match.group(1)
Out[5]: 'ch01'
In [6]: match.group(2)
Out[6]: 'seq001'
In [7]: match.group(3)
Out[7]: 's0090'
In [8]: match = re.search(r'ch(\d{2})\\seq(\d{3})\\s(\d{4})', path)
In [9]: print match.groups()
('01', '001', '0090')
On Oct 1, 2013, at 11:06 PM, Panupat Chongstitwattana wrote:
> Hi.
>
> I have this string
>
> path = r'P:\<various directories>\scene\ch01\seq001\s0090\anim\.......'
>
> I want to split out the ch01, seq001 and s0090 into 3 variables (or a list).
> Is there a way to do this with regex in a single line? Maybe with
> re.split(...)
>
> Currently I do it in 3 different steps
>
> find = re.findall(r'ch\d\d', path)
> if find: ch = find[0]
>
> find = re.findall(r'seq\d\d', path)
> if find: seq = find[0]
>
> etc.
>
> Thanks
>
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