not sure if someone answered this already, but here you go:
>>> re.findall(r'(?:ch\d{2})|(?:seq\d{2})|(?:s\d{4})', r'P:\<various
directories>\scene\ch01\seq001\s0090\anim\.......')
['ch01', 'seq00', 's0090']
{2} means repeat the pattern 2 times
?: means do not capture inside these parentheses
On Fri, Nov 8, 2013 at 5:35 AM, <[email protected]> wrote:
> asd
> On Tuesday, October 1, 2013 3:36:55 PM UTC+5:30, Panupat Chongstitwattana
> wrote:
> > Hi.
> >
> > I have this string
> >
> > path = r'P:\<various directories>\scene\ch01\seq001\s0090\anim\.......'
> >
> > I want to split out the ch01, seq001 and s0090 into 3 variables (or a
> list). Is there a way to do this with regex in a single line? Maybe with
> re.split(...)
> >
> > Currently I do it in 3 different steps
> >
> > find = re.findall(r'ch\d\d', path)
> > if find: ch = find[0]
> >
> > find = re.findall(r'seq\d\d', path)
> > if find: seq = find[0]
> >
> > etc.
> >
> > Thanks
>
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