Hello Jeremy,
One thing i found very usefull is the groups method of re.match,
so you can get parts of the matched pattern
for example,

>>> import re
>>> st = 'hello_v001'
>>> regex = '(.*)_[vV]([0-9]{3})$' # notice the ( ) to separate the parts
you get later, the $ represents the end of the string, the .* will match
anything
>>> re.match(regex, st)
<_sre.SRE_Match object at 0x01DC53C8>
>>> r = re.match(regex, st)
>>> r.groups()
('hello', '001')

Cheers!
Eduardo




On Sun, May 4, 2014 at 8:18 AM, Justin Israel <[email protected]>wrote:

> The re module also has a case insensitive flag:
>
> re.search(r'_v\d+', 'hello_v001', re.I)
>
> You can also limit it to a 3 padded version scheme if you want to go that
> far:
>
> re.search(r'_v\d{3}', 'hello_v001', re.I)
> On May 4, 2014 11:07 PM, "Anthony Tan" <[email protected]> wrote:
>
>> If the leading 'v' is the relevant thing, would '_[Vv][0-9]+' do?
>>
>> (Its just hunting for an underscore, lowercase OR uppercase v, then a
>> string of numbers)
>>  On 4 May 2014 20:47, Jeremy YeoKhoo <[email protected]> wrote:
>>
>> Hey guys,
>>
>> This should be fairly easy for you guys who know regex. If I have a
>> string that I want to enable versioning, so say for an example I want to
>> recognize a string if it contains ['v001', 'v002', etc...]
>> I have something like this...
>>
>> remp= re.search('[0-9]+', 'hello_v001')
>> print temp.group()
>>
>> but I dont want it to return when:
>> remp= re.search('[0-9]+', 'hello_001')
>> print temp.group()
>>
>> Thanks
>> -Jeremy
>>
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-- 
Eduardo GraƱa
www.eduardograna.com.ar

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