import pymel.core as pm
sel = pm.ls(sl=1, fl=True)
connectedVertGroups = {}
vertGroups = {}for i, vtx in enumerate(sel):
vtxKey = next((key for key, vtx_list in
connectedVertGroups.iteritems() if vtx in vtx_list), None)
if vtxKey is None:
connectedVerts = [ vert for vert in vtx.connectedVertices() ]
connectedVerts.append(vtx)
connectedVertGroups["group_{0}".format(i)] = connectedVerts
vertGroups["group_{0}".format(i)] = vtx
On 8 October 2014 18:05, Marcus Ottosson <[email protected]> wrote:
> How about a loop?
>
> awesome_verts = list()for name, group in connectedVertGroups.iteritems():
> for vertex in group:
> if vertex is 'Awesome':
> awesome_verts.append(vertex)
>
>
>
> On 8 October 2014 17:56, <[email protected]> wrote:
>
>> Hi jack, thx for helping me.
>>
>> I think this works for me:
>>
>> vtxKey = next((key for key, value in connectedVertGroups.iteritems() if
>> value == vtx), None)
>>
>> The only problem I'm having is that my dictionary values are a list of
>> vertices, and I need to check for a vertex within those lists.
>>
>> Do you have any suggestions for getting passed that? I was able to use
>> chain(*) when checking the dictionary values directly, but it doesn't seem
>> to work when I'm using dict.iteritems(). chain(*dict.iteritems()) or
>> chain(*dict.items()) - too many items to unpack.
>>
>> Kev
>>
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>
>
>
> --
> *Marcus Ottosson*
> [email protected]
>
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