Hi Jude
On Wed, Dec 29, 2010 at 9:11 AM, jude mwenda <[email protected]> wrote: > Hi all, > > I have been building a plugin and reached a dead end. I am parsing the csv > resource into a variable. but according to the qgis documentation, the > resource has to be a file. Can it be a variable. the code section that has > this issue is > results = ft_client.query(SQL().select(371443,None,None)) > > uri = results."?delimiter=%s&xField=%s&yField=%s" % (",", "Address", > "LONGITUDE") > vlayer = QgsVectorLayer(uri, "layer_name_you_like", "delimitedtext") > there is something very wrong with the uri section of the code. the docs > just use file paths, what of a variable as is my case? How would i go about > loading this. Please help Possibly your issue arises from the fact that you cannot perform sql type queries on delimited text layers. Try add a delimited layer to QGIS interactively and you will see the Layer->Query option for that layer is disabled. Regards Tim > -- > Regards, > > Jude Mwenda > Skype id: jmwenda > Twitter: www.twitter.com/judemwenda > > "Was ist mein Leben, wenn ich nicht mehr nützlich für andere." > Johann Wolfgang von Goethe > > _______________________________________________ > Qgis-developer mailing list > [email protected] > http://lists.osgeo.org/mailman/listinfo/qgis-developer > > -- Tim Sutton - QGIS Project Steering Committee Member (Release Manager) ============================================== Please do not email me off-list with technical support questions. Using the lists will gain more exposure for your issues and the knowledge surrounding your issue will be shared with all. Visit http://linfiniti.com to find out about: * QGIS programming and support services * Mapserver and PostGIS based hosting plans * FOSS Consulting Services Skype: timlinux Irc: timlinux on #qgis at freenode.net ============================================== _______________________________________________ Qgis-developer mailing list [email protected] http://lists.osgeo.org/mailman/listinfo/qgis-developer
