On Wed, Dec 29, 2010 at 8:11 AM, jude mwenda <[email protected]> wrote: > Hi all, > > I have been building a plugin and reached a dead end. I am parsing the csv > resource into a variable. but according to the qgis documentation, the > resource has to be a file. Can it be a variable. the code section that has > this issue is > results = ft_client.query(SQL().select(371443,None,None)) > > uri = results."?delimiter=%s&xField=%s&yField=%s" % (",", "Address", > "LONGITUDE") > vlayer = QgsVectorLayer(uri, "layer_name_you_like", "delimitedtext") > there is something very wrong with the uri section of the code. the docs > just use file paths, what of a variable as is my case? How would i go about > loading this. Please help
Jude, you have to save the contents of your variable to a temporary file and then load that file as a vector layer. Martin _______________________________________________ Qgis-developer mailing list [email protected] http://lists.osgeo.org/mailman/listinfo/qgis-developer
