It never fails, you can work on something forever and not figure it out but
the minute you post a question you see the answer. The way to add state to a
button is with addState() method, DOH! The only thing I did discover was
that the older constants that I had a note on do not work and all you need
to do is pass in the string 'pressed' to the method. So it simply looks
like:
btn.addState('pressed')
or
btn.removeState('pressed');
Jim
On 9/18/07, Jim Hunter <[EMAIL PROTECTED]> wrote:
>
> I may just be brain dead but I can't find a way to present a button in the
> 'pressed' position? What I have is a toolbar with a button to bring up a
> filter dialog. And if the filter is active, I want the filter button to stay
> 'pressed'. Then once the button is clicked again, I can see that it is
> 'pressed' and clear the filter and 'unpress' the button. I am using a
> qc.ui.toolbar.Button, how would I go about this seemingly trivial thing?
>
> Thanks,
> Jim
> www.D4PHP.org
> www.D4PHP-Hosting.com
>
>
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