Some things are really easy, are they? ;)
Sebastian
Am 19.09.2007 um 01:16 schrieb Jim Hunter:
It never fails, you can work on something forever and not figure it
out but the minute you post a question you see the answer. The way
to add state to a button is with addState() method, DOH! The only
thing I did discover was that the older constants that I had a note
on do not work and all you need to do is pass in the string
'pressed' to the method. So it simply looks like:
btn.addState('pressed')
or
btn.removeState('pressed');
Jim
On 9/18/07, Jim Hunter < [EMAIL PROTECTED]> wrote:
I may just be brain dead but I can't find a way to present a button
in the 'pressed' position? What I have is a toolbar with a button
to bring up a filter dialog. And if the filter is active, I want
the filter button to stay 'pressed'. Then once the button is
clicked again, I can see that it is 'pressed' and clear the filter
and 'unpress' the button. I am using a qc.ui.toolbar.Button, how
would I go about this seemingly trivial thing?
Thanks,
Jim
www.D4PHP.org
www.D4PHP-Hosting.com
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