Does it still fail if you use two different variables for the two list
items instead of the same 'xx' variable?
Gene
On Tue, 2009-12-15 at 18:07 -0500, Ken MacDonald wrote:
> I've collapsed the test case to this:
>
> (menuCombo is the SelectBox() defined elsewhere)
> var xx = new qx.ui.form.ListItem('foo', null);
> this.menuCombo.add(xx);
> xx = new qx.ui.form.ListItem('foo2', null);
> this.menuCombo.add(xx);
> this.menuCombo.removeAll(); // dies
>
> Ken
>
>
> On Tue, Dec 15, 2009 at 5:31 PM, Ken MacDonald <[email protected]>
> wrote:
>
> I have a form.SelectBox() and have added 2 items to the
> selection, added a listener but I think that's about it for
> what's happened to that widget. I think maybe I set some
> userData() on it, as well.
>
> On my form I have a 'reset' button, which I want to reload the
> app from the DB, including the select box. So I've tried
> doing:
>
> selectbox.removeAll() to attempt to remove the two items I
> added so I can add them again, but it blows up at that point,
> firebug goes off somewhere (?) and I'm not sure where it ends
> up. I also tried removing the children individually after
> doing a getChildren() and it fails on removal of the 2nd
> child, not the first.
>
> I was just able to trace a bit farther, and it's hitting this
> in Widget.js:
>
> this.assertNotUndefined(child);
> 2134 this.assertIdentical(child.getLayoutParent(), this,
> "Remove Error: " + child + " is not a child of this widget!");
>
> Is this a bug in remove()? It should not be trying to remove
> things it doesn't have, or alternately it's making a mistake
> thinking that this child is not one of it's children, since
> the child was just returned by getChildren().
> Ken
>
>
>
>
>
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