Sorry for the new topic, but I found another angle of view on the same problem which was written in another topic. Nobody answered there.
In the Application.js I initialize a firstLayer wich holds my app elements, and a secondLayer which is derived from the qx.ui.popup.Popup. A button click in the firstLayer calls a function buttonClicked() which needs a little time to execute, therefore the first row of this function is secondLayer.show() and the last row is secondLayer.hide(). The problem is, that qx ignores the order of my commands. The secondLayer won't show up not even the executing of the buttonClicked() function last more seonds. If I comment out the secondLayer.hide() I can see what's happening: the code in the buttonClicked() function is executed and only _after_ that the secondLayer.show() is executed, in spite of that this is the first row of the function. Does anybody experienced something like this? Does anybody know a solution for this? Any help would be greatly appreciated. Thanks. -- View this message in context: http://n2.nabble.com/bug-qx-ignores-popup-show-tp4479113p4479113.html Sent from the qooxdoo mailing list archive at Nabble.com. ------------------------------------------------------------------------------ The Planet: dedicated and managed hosting, cloud storage, colocation Stay online with enterprise data centers and the best network in the business Choose flexible plans and management services without long-term contracts Personal 24x7 support from experience hosting pros just a phone call away. http://p.sf.net/sfu/theplanet-com _______________________________________________ qooxdoo-devel mailing list qooxdoo-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/qooxdoo-devel
