Hi, Christian
Thank you very much for your help.
Your solution is perfetly working in the playground.
But after 2 days of experiencing I couldn't get it to work in real life
situation (where the show() and hide() pairs aren't on the same place).
I'll try to explain the structure I have and in which the timering doesn't
solve the problem.
I have a singleton class secondLayer. I added to this a widget (fadeLayer)
with an opacity value 0.4 and with backgroundColor black.
I use this second layer in two cases:
1. when I want to display a modal window ("Are you sure you want to delete?
Yes - No" stuff) the faderWidget is visible so the secondLayer acts like a
visual fader above the main content.
2. when I would like to display a loader.gif if the processes will take long
time. In this case the second layer acts as the holder of this gif in the
center of the screen.
(So the secondLayer has 3 important members: fadeLayer, loaderLayout,
modalWindow)
In order to acheve easy manipulation on second layer, it has a property
called state:
<code>
state: {
init: "Invisible",
apply: "stateChanged",
check: function(value) {
return value == "Invisible" || value == "Loader" || value ==
"ModalWindow";
}
}
</code>
And the function which is called when the state has been changed:
<code>
stateChanged : function() {
switch (this.getState()) {
case "Invisible" :
this.modalWindow.hide();
this.hide();
qx.ui.core.queue.Manager.flush();
break;
case "Loader" :
this.fadeLayer.setOpacity(0);
this.loaderLayout.show();
this .show();
qx.ui.core.queue.Manager.flush();
break;
case "ModalWindow" :
this.fadeLayer.setOpacity(0.4);
this.loaderLayout.hide();
this.modalWindow.show();
this.show();
break;
}
}
</code>
And of course I have in the application a few places where I change the
"state" property of the istance of the secondLayer.
I tried to put qx.event.Timer.once(function(e) {…}, this, 0); to some places
in my code, but unfortunatelly it didn't help :(
Maybe after this shot explanation of my problem you could give me a good
idea how to step forward.
And once again thank you very much for help (and your time).
Daniel
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