Thanks for the quick answers. So, the answer is a definite 'no' on that one.
Cheers, a|x ----- Original Message ---- From: Steve Mokris <[EMAIL PROTECTED]> To: Quartz Composer Dev List dev <[email protected]> Sent: Friday, 8 August, 2008 2:50:30 PM Subject: Re: Integrator Reset > However, at such large values you loose lots of low-value precision > (i.e. 1e300 + 1.0 == 1e300), so depending on the kind of data you're > working with that might become a problem. So therefore I think the original question could be restated as something like: "If you're accumulating at 1000.0 units per second, how long until Integrator stops working because the accumulated value is so much larger than the delta, that adding the delta has no appreciable effect?" ...and there's maybe a chance the answer to this question could be relevant within our universe's lifespan. Some quick theoretical calculations I performed suggest that it starts to lose accuracy around 1e16 (when incrementing by 1000.0), and loses all hope around 1e19. Thus Integrator can safely be used for about 1e13 seconds, or about 317,000 years. So for most purposes this should be fine, but it probably wouldn't be acceptable to the Long Now Foundation. :^) Steve _______________________________________________ Do not post admin requests to the list. They will be ignored. Quartzcomposer-dev mailing list ([email protected]) Help/Unsubscribe/Update your Subscription: http://lists.apple.com/mailman/options/quartzcomposer-dev/the_voder%40yahoo.co.uk This email sent to [EMAIL PROTECTED] __________________________________________________________ Not happy with your email address?. Get the one you really want - millions of new email addresses available now at Yahoo! http://uk.docs.yahoo.com/ymail/new.html
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