Hello, in NTP FAQ 5.1.2.3. (http://www.ntp.org/ntpfaq/NTP-s-algo.htm) it is standing: [...] 00000000000000000000000000000001 10000000000000000000000000000000
equals a decimal 1.5. The multipliers to the right of the point are 1/2, 1/4, 1/8, 1/16, etc. [...] If I understand it right, the binary calculation goes then from left-to-right, so it represents the normal binary, like 00000000000000000000000000000001 (1 in decimal); but why is the multiplier then 1/2? And how should the other multiplier looks like (e.g. 1/4; I would have thought it has to be 00100000000000000000000000000000 then?!) As far as I understand, the integer part is calculated as a normal binary (001 = 1, 010 = 2, etc.) Can somebody clearify the order of bits in NTP for me, please? Thanks in advance! Franz _______________________________________________ questions mailing list [email protected] https://lists.ntp.isc.org/mailman/listinfo/questions
