Very nice, Phil. Thank you.
-----Original Message-----
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Monday, September 20, 2010 1:28 PM
To: Doran, Harold
Cc: R-help
Subject: Re: [R] Sorting and subsetting
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(foo,index,seq))<=5)
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Mon, 20 Sep 2010, Doran, Harold wrote:
> Suppose I have a data frame, such as the one below:
>
> tmp <- data.frame(index = gl(2,20), foo = rnorm(40))
>
> And further assume it is sorted by index and then by the variable foo.
>
> tmp <- tmp[order(tmp$index, tmp$foo) , ]
>
> Now, I want to grab the first N rows of tmp for each index. In the end, what
> I want is the data frame 'result'
>
> tmp1 <- subset(tmp, index == 1)
> tmp2 <- subset(tmp, index == 2)
>
> tmp1 <- tmp1[1:5,]
> tmp2 <- tmp2[1:5,]
> result <- rbind(tmp1, tmp2)
>
> Does anyone see a way to subset and subsequently bind without a loop?
>
> Harold
>
>
>
> [[alternative HTML version deleted]]
>
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