On Dec 1, 2011, at 10:49 AM, lincoln wrote:
Thanks.
So, suppose for one specific year (first year over 10) the
percentage of
successes deriving from 100 trials with 38 successes (and 62
failures), its
value would be 38/100=0.38.
I could calculate its confidence intervals this way:
success<-38
total<-100
prop.test(success,total,p=0.5,alternative="two.sided")
1-sample proportions test with continuity
correction
data: success out of total, null probability 0.5
X-squared = 5.29, df = 1, p-value = 0.02145
alternative hypothesis: true p is not equal to 0.5
95 percent confidence interval:
0.2863947 0.4829411
sample estimates:
p
0.38
So it would be var$1=0.38 , CI=0.286-0.483
Is it correct?
I couldn't tell if this were homework, so I just threw out a starting
point. If you were told to do a resampling method then this would just
be a starting point and you would be expected to go further with the
boot function.
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