Not sure what you mean by mean of each position, so here are two
possibilities: rowMeans and colMeans:
> x1<-as.vector(rnorm(10))
> x2<-as.vector(rnorm(10))
> x3<-as.vector(rnorm(10))
> x4<-as.vector(rnorm(10))
> x5<-as.vector(rnorm(10))
> x6<-as.vector(rnorm(10))
> x7<-as.vector(rnorm(10))
> x8<-as.vector(rnorm(10))
> x9<-as.vector(rnorm(10))
> x10<-as.vector(rnorm(10))
>
> # create matrix
> x1.6 <- rbind(x1, x2, x3, x4, x5, x6)
> rowMeans(x1.6)
x1 x2 x3 x4 x5 x6
-0.7845288 0.3254140 -0.4430038 -0.1533713 0.6074253 -0.1560222
> colMeans(x1.6)
[1] 0.23480212 -0.08486182 -0.28657007 -0.59151369 0.08995106
0.55138690 -0.22388657
[8] -0.36354109 -0.20111151 -0.13146655
>
On Mon, Dec 19, 2011 at 11:00 AM, Pablo <pschatfi...@gmail.com> wrote:
> Suppose I have the following:
>
> x1<-as.vector(rnorm(10))
> x2<-as.vector(rnorm(10))
> x3<-as.vector(rnorm(10))
> x4<-as.vector(rnorm(10))
> x5<-as.vector(rnorm(10))
> x6<-as.vector(rnorm(10))
> x7<-as.vector(rnorm(10))
> x8<-as.vector(rnorm(10))
> x9<-as.vector(rnorm(10))
> x10<-as.vector(rnorm(10))
>
> I would like the mean of x1 to x6 for each vector position. I would do
> something else with x7-x10. These vectors are not currently in a dataframe.
> I tried to be clever by trying get(paste(paste("x", 1:6, sep=""),
> collapse="+")) but it didn't work. Any thoughts are greatly appreciated,
>
> Pablo
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Summing-x1-to-x6-tp4214604p4214604.html
> Sent from the R help mailing list archive at Nabble.com.
>
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--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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