On Dec 19, 2011, at 11:00 AM, Pablo wrote:
Suppose I have the following:
x1<-as.vector(rnorm(10))
x2<-as.vector(rnorm(10))
x3<-as.vector(rnorm(10))
x4<-as.vector(rnorm(10))
x5<-as.vector(rnorm(10))
x6<-as.vector(rnorm(10))
x7<-as.vector(rnorm(10))
x8<-as.vector(rnorm(10))
x9<-as.vector(rnorm(10))
x10<-as.vector(rnorm(10))
I would like the mean of x1 to x6 for each vector position.
> apply( data.frame(x1,x2,x3,x4,x5,x6), 1, mean)
[1] -0.39321854 -0.92940746 -0.04843466 -0.27764111 0.44058599
0.73512759
[7] -0.22232332 -0.89535287 -0.33430655 0.66217526
> apply( matrix(c(x1,x2,x3,x4,x5,x6),ncol=6), 1, mean)
[1] -0.39321854 -0.92940746 -0.04843466 -0.27764111 0.44058599
0.73512759
[7] -0.22232332 -0.89535287 -0.33430655 0.66217526
After seeing Jim Holtman's suggestion, it should be clear that
rowMeans would work just even better than these `apply` solutions when
used with this "vertical" orientation of the vectors.
I would do
something else with x7-x10. These vectors are not currently in a
dataframe.
I tried to be clever by trying get(paste(paste("x", 1:6, sep=""),
collapse="+")) but it didn't work. Any thoughts are greatly
appreciated,
--
David Winsemius, MD
West Hartford, CT
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