Hello,

Since function splines::bs returns an object of class bs in order to read the help page for function predict you need

?predict.bs

The syntax would be

## S3 method for class 'bs'
predict(object, newx, ...)

Please read that help page and maybe you'll get the answer you need.

Hope this helps,

Rui Barradas

Em 28-05-2017 15:51, Glenn Schultz escreveu:
If is specify a spline basis as follows

knots <- c(6, 12, 22, 30, 35)
x <- c(0.0, .25, 1.0, 2.0, 3.0)
SCurve <- bs(x = x, knots = knots, intercept = FALSE, Boundary.knots =
c(0,3.5))

I would like to now get the spline value for new values of x.  However,
when I use predict the new basis is returned and I would like to get the
value.  Nothing has worked so far and ?predict plus examples only show
prediction from linear models.  Is there a way to extract the value from
a defined spline?

Best Regards,
Glenn
______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to