Looks like it is not exported from the package namespace... a packaging error. -- Sent from my phone. Please excuse my brevity.
On May 28, 2017 1:53:29 PM PDT, Rui Barradas <[email protected]> wrote: >Hello, > >Can anyone explain why this error? > > > library(splines) > > > > knots <- c(6, 12, 22, 30, 35) > > x <- c(0.0, .25, 1.0, 2.0, 3.0) >> SCurve <- bs(x = x, knots = knots, intercept = FALSE, Boundary.knots >= c(0,3.5)) > > class(SCurve) >[1] "bs" "basis" "matrix" > > > > ?predict.bs > > predict.bs(SCurve, xnew = 40:45) >Error in predict.bs(SCurve, xnew = 40:45) : > could not find function "predict.bs" > >Note that splines:::predict.bs(SCurve, xnew = 40:45) works. > > > sessionInfo() >R version 3.4.0 (2017-04-21) >Platform: x86_64-w64-mingw32/x64 (64-bit) >Running under: Windows 7 x64 (build 7601) Service Pack 1 > >Matrix products: default > >locale: >[1] LC_COLLATE=Portuguese_Portugal.1252 >LC_CTYPE=Portuguese_Portugal.1252 >[3] LC_MONETARY=Portuguese_Portugal.1252 LC_NUMERIC=C > >[5] LC_TIME=Portuguese_Portugal.1252 > >attached base packages: >[1] splines stats graphics grDevices utils datasets methods >[8] base > >loaded via a namespace (and not attached): >[1] compiler_3.4.0 tools_3.4.0 > > >Rui Barradas > > >Em 28-05-2017 17:37, Rui Barradas escreveu: >> Hello, >> >> Since function splines::bs returns an object of class bs in order to >> read the help page for function predict you need >> >> ?predict.bs >> >> The syntax would be >> >> ## S3 method for class 'bs' >> predict(object, newx, ...) >> >> Please read that help page and maybe you'll get the answer you need. >> >> Hope this helps, >> >> Rui Barradas >> >> Em 28-05-2017 15:51, Glenn Schultz escreveu: >>> If is specify a spline basis as follows >>> >>> knots <- c(6, 12, 22, 30, 35) >>> x <- c(0.0, .25, 1.0, 2.0, 3.0) >>> SCurve <- bs(x = x, knots = knots, intercept = FALSE, Boundary.knots >= >>> c(0,3.5)) >>> >>> I would like to now get the spline value for new values of x. >However, >>> when I use predict the new basis is returned and I would like to get >the >>> value. Nothing has worked so far and ?predict plus examples only >show >>> prediction from linear models. Is there a way to extract the value >from >>> a defined spline? >>> >>> Best Regards, >>> Glenn >>> ______________________________________________ >>> [email protected] mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >> >> ______________________________________________ >> [email protected] mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > >______________________________________________ >[email protected] mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
