> -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf Of maram salem > Sent: Tuesday, October 13, 2009 2:13 PM > To: r-help > Subject: [R] cdf > > Dear all, > I have the cdf of the following power fuction distribution: > F(y)=(y/350)^a ,0<y<350, > where " a " is some parameter with range a>0. > I want to use it as the argument of the discretize function of the actuar > package. > > So I think I need to define this function to R so that if I entered a=1, I > get the > following > F(y)=(y/350) > and if I entered a=4.5, I get the following > F(y) =(y/350)^4.5 > ........... and so on > > I've tried > a<-vector(mode="numeric",length=1) > powercdf<-function(a,y) > (y/350)^a > > But when I typed: powercdf(10,y) > instead of getting : (y/350)^10 (which is what I want) > I got : object y not found ?? > > I want y to remain as it is, a continous variable, not for example seq(0,350). > Thank you in advance. > Maram >
You say "I want y to remain as it is, ...". where is y defined outside of your function? Dan Daniel J. Nordlund Washington State Department of Social and Health Services Planning, Performance, and Accountability Research and Data Analysis Division Olympia, WA 98504-5204 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.