On Oct 13, 2009, at 5:12 PM, maram salem wrote:
Dear all,
I have the cdf of the following power fuction distribution:
F(y)=(y/350)^a ,0<y<350,
where " a " is some parameter with range a>0.
I want to use it as the argument of the discretize function of the
actuar package.
So I think I need to define this function to R so that if I entered
a=1, I get the following
F(y)=(y/350)
and if I entered a=4.5, I get the following
F(y) =(y/350)^4.5
........... and so on
I've tried
a<-vector(mode="numeric",length=1)
powercdf<-function(a,y)
(y/350)^a
But when I typed: powercdf(10,y)
instead of getting : (y/350)^10 (which is what I want)
I got : object y not found ??
I want y to remain as it is, a continous variable, not for example
seq(0,350).
Thank you in advance.
If you want symbolic algebra then use a system designed for such. If
you invoke a function in R you need to give it arguments for
evaluation ... to numerical values.
If you want a function that returns a function, that is also possible.
> cdffn <- function(y, arg) return( function(y) {y^arg} )
> cdf10 <- cdffn(y, 10)
> cdf10(1:10)
[1] 1 1024 59049 1048576 9765625
60466176 282475249 1073741824
[9] 3486784401 10000000000
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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