Look at the strapply function in the gsubfn package. It may do what you want.
-- Gregory (Greg) L. Snow Ph.D. Statistical Data Center Intermountain Healthcare greg.s...@imail.org 801.408.8111 > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r- > project.org] On Behalf Of xin wei > Sent: Monday, June 07, 2010 11:21 AM > To: r-help@r-project.org > Subject: [R] how to parse out string separated by special character > > > hi, everyone: > i have a data frame with one single character column as followings: > DS_xxx_yyy_24hr_zzz_1 > DS_xxx_yyy_24hr_zzz_2 > DS_xxx_yyy_24hr_zzz_3 > DS_xxx_yyy_24hr_zzz_4 > DS_xxx_yyy_24hr_zzz_1 > DS_xxx_yyy_24hr_zzz_2 > DS_xxx_yyy_24hr_zzz_3 > DS_xxx_yyy_24hr_zzz_4 > DS_xxx_yyy_24hr_zzz_1 > > i need to parse out the time part like the followings: > name time > DS_xxx_yyy_24hr_zzz_1 24hr > DS_xxx_yyy_24hr_zzz_2 24hr > DS_xxx_yyy_24hr_zzz_3 24hr > DS_xxx_yyy_24hr_zzz_4 24hr > DS_xxx_yyy_24hr_zzz_1 24hr > DS_xxx_yyy_24hr_zzz_2 24hr > DS_xxx_yyy_24hr_zzz_3 24hr > DS_xxx_yyy_24hr_zzz_4 24hr > DS_xxx_yyy_24hr_zzz_1 24hr > > what function should I look at? > i have tried: strsplit(data, '_') and get a giant list which is not > what i > need. > > thanks in advance > > -- > View this message in context: http://r.789695.n4.nabble.com/how-to- > parse-out-string-separated-by-special-character-tp2246301p2246301.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.