cut returns a factor. Try something like t1 <- cut(data.vector, breaks = my.breaks, labels = my.label) as.numeric(as.character(t1))
This is an issue that comes up frequently with factor. Take a look at the help page for factor for some warnings. Hope this helps, Matt Wiener -----Original Message----- From: Nina Wawro [mailto:[EMAIL PROTECTED]] Sent: Wednesday, January 29, 2003 11:39 AM To: R-help Subject: [R] help on cut? Dear R-users, I'm trying to recode a variable. After using cut(data.vector,breaks=my.breaks,labels=my.label) I need the data.vector to have the same values as the labels. To make it clear: x<-runif(10) y<-cut(x,breaks=c(0,0.3,0.7,0.9,1),labels=c(3,6,7,9)) as.numeric(y) returns something like a vector 1 3 3 2 2 1 4 2 3 4 . I need something like 3 7 7 6 6 3 7 9 6 7 9 for further use. I might be using the wrong function but a loop seems to be inefficient as I need to do it about 60 times with varying length of labels Is there a quick solution? Thanks for any help in advance! Nina Wawro R.1.6.0 on Windows2000 ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help ------------------------------------------------------------------------------ ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
