> Dear R-users, > > I'm trying to recode a variable. > After using > cut(data.vector,breaks=my.breaks,labels=my.label) > I need the data.vector to have the same values as the labels. > > > To make it clear: > x<-runif(10) > y<-cut(x,breaks=c(0,0.3,0.7,0.9,1),labels=c(3,6,7,9)) > as.numeric(y) returns something like a vector 1 3 3 2 2 1 4 2 3 4 . > I need something like 3 7 7 6 6 3 7 9 6 7 9 for further use.
y is a factor and you want a numeric representing the factor labels, this is in section 7.12 of the R-FAQ: R> x<-runif(10) R> y<-cut(x,breaks=c(0,0.3,0.7,0.9,1),labels=c(3,6,7,9)) R> y [1] 3 7 9 3 6 6 7 7 3 6 Levels: 3 6 7 9 R> as.numeric(as.character(y)) [1] 3 7 9 3 6 6 7 7 3 6 Torsten > > I might be using the wrong function but a loop seems to be inefficient as I > need to do it about 60 times with varying length of labels > Is there a quick solution? > Thanks for any help in advance! > > Nina Wawro > > R.1.6.0 on Windows2000 > > ______________________________________________ > [EMAIL PROTECTED] mailing list > http://www.stat.math.ethz.ch/mailman/listinfo/r-help > > ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
