Ok, let me put it the other way around. On another test I have W = 0.9907, p-value = 6.024e-06. The same question stands, with such huge W should it be expected to be normal ?
EJ On Mon, 2003-02-10 at 14:47, Richard A. Bilonick wrote: > Ernesto Jardim wrote: > > >Hi > > > >The shapiro.test function outputs a value of the W statistic, which > >should be 1 if the distribution is normal, and a p-value for the test > >(as the documentation states). > > > >I'm a bit confused with some results. I'm getting a W=0.9977 and a > >p-value=0.1889. > > > >I was expecting that a W of 0.9977 would tell me that the distribution > >is normal so p-value should be small ... > > > >What am I missing ? > > > >Thanks > > > >EJ > > > >______________________________________________ > >[EMAIL PROTECTED] mailing list > >http://www.stat.math.ethz.ch/mailman/listinfo/r-help > > > > > > > > > You have it backwards. The null hypothesis is that the distribution is > Normal. You reject this null when the p-value is small. If the > distribution is Normal, the p-value will tend to be large. > > > shapiro.test(rnorm(100)) > > Shapiro-Wilk normality test > > data: rnorm(100) > W = 0.9877, p-value = 0.4894 > > > Rick B. > > ______________________________________________ > [EMAIL PROTECTED] mailing list > http://www.stat.math.ethz.ch/mailman/listinfo/r-help ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
