I didn't noticed that fact. I've already found a way to do that
x <- 1:40
colnames(df.treino) <- paste("Ncp",x,sep=".")
and this generates names that I can relate with the variables. Thanks anyway
The problem is that I use rpart in a loop and the class labels are in the last column.
For the above example I would "type"
rpart(Ncp.40~.,data=df.treino)
But in the next step of the loop I can have only 35 variables and the class labels
would be at the Ncp.36. So I have to refresh the formula in rpart... and that is my
problem
-----Original Message-----
From: Torsten Hothorn [mailto:[EMAIL PROTECTED]
Sent: Tue 22/07/2003 14:57
To: Luis Miguel Almeida da Silva
Cc: [EMAIL PROTECTED]
Subject: Re: [R] variable names
On Tue, 22 Jul 2003, Luis Miguel Almeida da Silva wrote:
> Dear helpers
>
> I want to use rpart several times in a loop to build a classification tree.
My problem is that rpart needs a formula as argument and for that the variables need
to have names and this doesn't happen in my case. Every iteration in the loop has a
different dataset with several variables (ex. 38 or more) and so I can't type the
names by hand every time. Is there any function that generates names for variables in
a dataframe. If so, how can I use then the argument
>
If your data is organised in a data.frame, (dummy) variable names are
available by default:
R> mydata <- data.frame(matrix(rnorm(25), ncol=5))
R> mydata
X1 X2 X3 X4 X5
1 1.3806313 -0.41827136 0.9591628 -1.3351038 0.02746110
2 0.5114590 -1.34111439 -0.9617552 -0.8367088 -0.06913021
3 -1.7508089 -0.49387076 -1.7597395 2.3899490 -0.15209650
4 -1.6753809 -1.28381808 -1.0424903 0.1002998 0.27784949
5 -0.2605535 -0.09035652 -2.5786418 1.0483400 -0.70445615
R> rpart(X1 ~ ., data = mydata)
n= 5
node), split, n, deviance, yval
* denotes terminal node
1) root 5 7.463698 -0.3589306 *
best,
Torsten
> rpart(classlabels~. ,.....)
>
> thanks
>
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