Read Bill Venables' column in R News issue 2/2, page 24.

Andy

> From: Luis Miguel Almeida da Silva [mailto:[EMAIL PROTECTED] 
> 
> I didn't noticed that fact. I've already found a way to do that
>  
> x <- 1:40
> colnames(df.treino) <- paste("Ncp",x,sep=".")
>  
> and this generates names that I can relate with the 
> variables. Thanks anyway
>  
> The problem is that I use rpart in a loop and the class 
> labels are in the last column. For the above example I would "type"
>  
> rpart(Ncp.40~.,data=df.treino)
>  
> But in the next step of the loop I can have only 35 variables 
> and the class labels would be at the Ncp.36. So I have to 
> refresh the formula in rpart... and that is my problem
> 
>       -----Original Message----- 
>       From: Torsten Hothorn [mailto:[EMAIL PROTECTED] 
>       Sent: Tue 22/07/2003 14:57 
>       To: Luis Miguel Almeida da Silva 
>       Cc: [EMAIL PROTECTED] 
>       Subject: Re: [R] variable names
>       
>       
> 
> 
>       On Tue, 22 Jul 2003, Luis Miguel Almeida da Silva wrote:
>       
>       > Dear helpers
>       > 
>       > I want to use rpart several times in a loop to build 
> a classification tree. My problem is that rpart needs a 
> formula as argument and for that the variables need to have 
> names and this doesn't happen in my case. Every iteration in 
> the loop has a different dataset with several variables (ex. 
> 38 or more) and so I can't type the names by hand every time. 
> Is there any function that generates names for variables in a 
> dataframe. If so, how can I use then the argument
>       > 
>       
>       If your data is organised in a data.frame, (dummy) 
> variable names are
>       available by default:
>       
>       R> mydata <- data.frame(matrix(rnorm(25), ncol=5))
>       R> mydata
>                 X1          X2         X3         X4          X5
>       1  1.3806313 -0.41827136  0.9591628 -1.3351038  0.02746110
>       2  0.5114590 -1.34111439 -0.9617552 -0.8367088 -0.06913021
>       3 -1.7508089 -0.49387076 -1.7597395  2.3899490 -0.15209650
>       4 -1.6753809 -1.28381808 -1.0424903  0.1002998  0.27784949
>       5 -0.2605535 -0.09035652 -2.5786418  1.0483400 -0.70445615
>       R> rpart(X1 ~ ., data = mydata)
>       n= 5
>       
>       node), split, n, deviance, yval
>             * denotes terminal node
>       
>       1) root 5 7.463698 -0.3589306 *
>       
>       best,
>       
>       Torsten
>       
>       > rpart(classlabels~. ,.....)
>       > 
>       > thanks
>       >
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>       >
>       >
> 
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