Hello, and thanks for this. > From "www.r-project.org" -> search -> "R site search" -> "LD50", I found > "dose.p", described on p. 193, sec. 7.2, of Venables and Ripley (2002) Modern > Applied Statistics with S, 4th ed. (Springer).
I found the same, but this is for logistic regression I think, not Poisson. This is used to calculate the dose which causes 50% "death". I could do it this way by "pretending" my data is binomial. i/e Y/Ymax = some value between 0 and 1. I could "pretend" my response data is "dead" or "alive", but I'm not sure this is "proper". but maybe it is? Any hints on this? Y and Ymax follows a Poisson distribution. Can I just use Y/Ymax, run a logistic regression and go on with my life??? ;-) (LD50P100 <- dose.p(fitP100, p=14)) > Dose SE > p = 14: -2.451018 0.04858572 Wow, you got the dose.p function to work with poisson regression? but under SPlus only? is it giving the right results? ... my > present insomniac state (3:20 AM in California). The same for me!!! ;-) I worked on this 2:00AM EDT thanks and have a nice day, possibly starting with a good coffee!!! > M. PHILION: Does this provide sufficient information for you to now solve > your problem? If this works under R and is giving the right solution, I owe you BIG TIME ! bye for now, -- Vincent Philion, M.Sc. agr. Phytopathologiste Institut de Recherche et de D�veloppement en Agroenvironnement (IRDA) 3300 Sicotte, St-Hyacinthe Qu�bec J2S 7B8 t�l�phone: 450-778-6522 poste 233 courriel: [EMAIL PROTECTED] Site internet : www.irda.qc.ca ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
