On Wed, 10 Mar 2004, Liaw, Andy wrote: > That gives you a vector, not a data frame. > > The problem is that the object returned by tapply is a 1-d array of list. > When as.data.frame() is called, the default method doesn't know how to > handle arrays and gives the error. What you really want for this particular > case is to treat the object as a list, so the unorthodox way is: > > as.data.frame.list(xb) > > OK, I didn't really say that...
If this dataset barley from package lattice, it works in 1.9.0 alpha which does have as.data.frame.array. So the issue is about to go away. > > On Wednesday 10 March 2004 06:58, Wolfram Fischer wrote: > > > I have two lists: > > > > > > xa <- list( X=c(1,2,3), Y=c(4,5,6), Z=c(7,8,9) ) > > > > > > xb <- with( barley, tapply( X=seq(1:nrow(barley)), INDEX=site > > > , FUN=function(z)yield[z])) > > > > > > I can convert xa to a dataframe easily with: > > > as.data.frame(xa) > > > > > > But if i try the same with xb I get: > > > as.data.frame(xb) > > > Error in as.data.frame.default(xb) : > > > can't coerce array into a data.frame > > > > > > What helps? > > > > > > (NB: I know the formula for xb is stupid, but it generates the same > > > type of list as the list I get from my real problem.) > -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
