On 10 Mar 2004 at 15:58, Wolfram Fischer wrote: It's a bit strange. The following should work:
as.data.frame(as.matrix(xb)) Kjetil Halvorsen > I have two lists: > > xa <- list( X=c(1,2,3), Y=c(4,5,6), Z=c(7,8,9) ) > > xb <- with( barley, tapply( X=seq(1:nrow(barley)), INDEX=site > , FUN=function(z)yield[z])) > > I can convert xa to a dataframe easily with: > as.data.frame(xa) > > But if i try the same with xb I get: > as.data.frame(xb) > Error in as.data.frame.default(xb) : > can't coerce array into a data.frame > > What helps? > > (NB: I know the formula for xb is stupid, but it generates the same > type of list as the list I get from my real problem.) > > Wolfram > > ______________________________________________ > [EMAIL PROTECTED] mailing list > https://www.stat.math.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! > http://www.R-project.org/posting-guide.html ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
