Thank you so much for each of your responses. But to make sure I am
clear (in my own mind), is this correct?
If x = 2^y
Then y = log2(x)
Thanks again. I know this is basic.
...heather
Duncan Murdoch wrote:
On Wed, 24 Nov 2004 12:26:46 -0500, "Heather J. Branton" <[EMAIL PROTECTED]>
wrote :
Dear R-users,
I have a basic question about how to determine the antilog of a variable.
Say I have some number, x, which is a factor of 2 such that x = 2^y. I
want to figure out what y is, i.e. I am looking for the antilog base 2 of x.
I have found log2 in the Reference Manual. But I am struggling how to
get the antilog of that.
You seem to be confusing log with antilog, but log2(x) and 2^y are
inverses of each other, i.e.
log2(2^y) equals y
and
2^log2(x) equals x
(up to rounding error, of course).
Duncan Murdoch
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