Here's something that works. I'm sure there are better solutions (in particular the paste part - I couldn't figure out how to avoid typing a[i,1], ..., a[i,10]).
a <- matrix(nrow=1000,ncol=10) for (i in 1:1000) for (j in 1:10) a[i,j] <- sample(1:0,1) b <- vector(mode="character") for (i in 1:1000) b[i] <- paste(a[i,1],a[i,2],a[i,3],a[i,4],a[i,5], a[i,6],a[i,7],a[i,8],a[i,9],a[i,10],sep="") #the most frequent row table(b)[table(b) == max(table(b))] HTH, b. -----Original Message----- From: Lisa Pappas [mailto:[EMAIL PROTECTED] Sent: Thursday, December 09, 2004 5:15 PM To: [EMAIL PROTECTED] Subject: [R] finding the most frequent row I am bootstrapping using a function that I have defined. The "Statistic" of the function is an array of 10 numbers. Therefore if I use 1000 replications, the "t" matrix will have 1000 rows each of which is a bootstrap replicate of this 10 number array (10 columns). Is there any easy way in R to determine which row appears the most frequently? Thanks, Lisa Pappas Huntsman Cancer Institute wishes to promote open communication while protecting confidential and/or privileged information. If you have received this message in error, please inform the sender and delete all copies. ______________________________________________ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html ______________________________________________ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html