Yes, it is discrete, but the underlying distribution is Gaussian.

Just got the following from a college:

Var(mean of finite population) = ((N - n)/(N - 1)) * var(population) / n

This should be it...

Greetings,
Roy

-----Original Message-----
From: Liaw, Andy [mailto:[EMAIL PROTECTED] 
Sent: Wednesday, March 23, 2005 2:17 PM
To: Roy Werkman; [email protected]
Subject: RE: [R] Question on statistics

If the sample is drawn with replacement from the finite population, then
the usual formula applies (assuming iid samples); i.e., var(sample mean)
=
var(population) / n.

There's some problem in your description:  A finite population, I
believe, is necessarily discrete (since there are only N possible
values), so it can not be Gaussian (i.e., normal).

Andy

> From: Roy Werkman
> 
> Ehh, by limited distribution, I meant to say a population of N points.
> 
> ...
>  
> Hi,
> 
> Can anyone help me with the following (although not directly 
> correlated to R functionality)? I have been looking on the internet 
> but can not find the answer.
> 
> My question: what is the variation on the mean of a limited 
> distribution (total N points normally distributed), when I have a 
> small sample of that distribution (n < N)?
> 
> Your help would be very welcome.
> 
> Thanx,
> Roy
> 
> 
> --
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