You can list them together using "|" (which stands for 'or'):
c<-subset(c,!rownames(c) %in% grep(".1|.5|.6|.99999",rownames(c),value=T))
but "." means any character for regular expressions, so if you meant a
decimal place, you probably want to escape them with a "\\":
c<-subset(c,!rownames(c) %in%
grep("\\.1|\\.5|\\.6|\\.99999", rownames(c),value=T))
Another option is
c<-subset(c,regexpr("\\.1|\\.5|\\.6|\\.99999",c) < 0)
because regexpr will return -1 for elements which do not contain a match.
--- Ana Patricia Martins <[EMAIL PROTECTED]> wrote:
> Hello R-users and developers,
>
> Once again, I'm asking for your help.
>
> There is other way to do the same more easily for applied simultaneous
> grep???
>
> c<-subset(c,!rownames(c) %in% grep(".1",rownames(c),value=T))
> c<-subset(c,!rownames(c) %in% grep(".5",rownames(c),value=T))
> c<-subset(c,!rownames(c) %in% grep(".6",rownames(c),value=T))
> c<-subset(c,!rownames(c) %in% grep(".99999",rownames(c),value=T))
>
> Thanks in advance for helping me.
>
> Atenciosamente,
> Ana Patricia Martins
> -------------------------------------------
> Serviço Métodos Estatísticos
> Departamento de Metodologia Estatística
> INE - Portugal
> Telef: 218 426 100 - Ext: 3210
> E-mail: [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>
>
>
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>
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> and provide commented, minimal, self-contained, reproducible code.
>
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