What should (foo bar) return?
On Sep 16, 2011, at 3:46 PM, Daniel MacDougall wrote: > Is there any way to define a macro that expands out to a lambda, and then > access the arguments passed to that lambda from outside the macro in the > calling context? > Here's an example of what I mean: > > #lang racket > > (define-syntax-rule (foo form ...) > ((lambda (bar) form ...) "ARG")) > > (foo "Hello") ; => returns "Hello" > > (foo bar) ; => expand: unbound identifier in module in: bar > > > I'd like access to the "bar" argument on the last line. Is this possible with > Racket macros? > > Thanks, > Daniel > _________________________________________________ > For list-related administrative tasks: > http://lists.racket-lang.org/listinfo/users _________________________________________________ For list-related administrative tasks: http://lists.racket-lang.org/listinfo/users
