In this example it should return "ARG". On Fri, Sep 16, 2011 at 1:08 PM, Matthias Felleisen <[email protected]>wrote:
> > > What should (foo bar) return? > > > On Sep 16, 2011, at 3:46 PM, Daniel MacDougall wrote: > > > Is there any way to define a macro that expands out to a lambda, and then > access the arguments passed to that lambda from outside the macro in the > calling context? > > Here's an example of what I mean: > > > > #lang racket > > > > (define-syntax-rule (foo form ...) > > ((lambda (bar) form ...) "ARG")) > > > > (foo "Hello") ; => returns "Hello" > > > > (foo bar) ; => expand: unbound identifier in module in: bar > > > > > > I'd like access to the "bar" argument on the last line. Is this possible > with Racket macros? > > > > Thanks, > > Daniel > > _________________________________________________ > > For list-related administrative tasks: > > http://lists.racket-lang.org/listinfo/users > >
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