Yes, it's effectively in words (so 8 bytes on a 64-bit platform, 4
bytes on a 32-bit platform), since the count refers to Racket values
that are represented by pointers.
You can set the value to be a small as you want, since the stack is
grown as needed, but even the simplest program will need a dozen or so
words.
At Sun, 3 Sep 2017 15:23:30 -0400, Greg Hendershott wrote:
> Empirically it seems to be 8-byte words?
>
> Unless I made a mistake:
>
> #lang at-exp racket/base
>
> (require racket/format)
>
> (define (current-custodian-memory-use)
> (for ([_ (in-range 3)]) (collect-garbage))
> (current-memory-use (current-custodian)))
>
> (define (f v)
> (parameterize ([current-thread-initial-stack-size v]
> [current-custodian (make-custodian)])
> (define ch (make-channel))
> (thread
> (λ ()
> (channel-put ch (current-custodian-memory-use))))
> (channel-get ch)))
>
> (f 1024) ;=> 12944
> (f 2048) ;=> 21136
> (f 4096) ;=> 37520
>
> (define (diff v1 v2)
> (define f1 (f v1))
> (define f2 (f v2))
> @~a{Initial stack sizes of @v1 and @v2
> seem to consume @f1 and @f2 bytes respectively.
> Diff in stack sizes is @(- v2 v1).
> Diff in memory is @(- f2 f1).
> Factor is @(/ (- f2 f1) (- v2 v1)) bytes.})
>
> (displayln (diff 2048 4096))
> ;; Initial stack sizes of 2048 and 4096
> ;; seem to consume 21136 and 37520 bytes respectively.
> ;; Diff in stack sizes is 2048.
> ;; Diff in memory is 16384.
> ;; Factor is 8 bytes.
>
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