Hello list,
In the following program, racket thinks foo2, and foo3 are bound to
syntax. Is this expected behavior?
-- File: go.rkt
#lang racket
(module p racket
(provide (all-defined-out))
(define (foo0 a b)
(+ a b))
(define (foo1 a b [c 3])
(+ a b c))
(define (foo2 a b [c 3] #:kw1 kw1)
(+ a b c))
(define (foo3 a b [c 3] #:kw1 kw1 #:kw2 [kw2 1])
(+ a b c))
)
(require syntax/location)
(define ns (make-base-empty-namespace))
(parameterize ([current-namespace ns])
(namespace-require (quote-module-path p)))
(namespace-variable-value 'foo0 #t #f ns) ; OK
(namespace-variable-value 'foo1 #t #f ns) ; OK
(namespace-variable-value 'foo2 #t #f ns) ; namespace-variable-value:
bound to syntax in: foo2
(namespace-variable-value 'foo3 #t #f ns) ; namespace-variable-value:
bound to syntax in: foo3
--
You received this message because you are subscribed to the Google Groups
"Racket Users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to racket-users+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.
