I think it is something more. The copied set is giving completely different 
elements. If i loop over the copied set i get 32 values from 0 to like 31, when 
i have in fact added 1000 random elements to the original set before copying.

Nate

> On Dec 8, 2020, at 6:43 PM, Robby Findler <ro...@cs.northwestern.edu> wrote:
> 
> No, I don't think that's it. The issue is that one is a mutable set and the 
> other isn't, so they aren't equal (even if their elements aren't equal).
> 
> > (equal? (mutable-seteqv) (list->seteqv '()))
> #f
> 
> Maybe you wanted to call list->mutable-seteqv? Or maybe just start with an 
> immutable set?
> 
> Robby
> 
> 
> On Tue, Dec 8, 2020 at 6:40 PM Nathaniel W Griswold <nate@manicmind.earth> 
> wrote:
> Thanks. Switching to 7.9 now.
> 
> Nate
> 
> > On Dec 8, 2020, at 6:38 PM, Jon Zeppieri <zeppi...@gmail.com> wrote:
> > 
> > I think that's this bug
> > [https://github.com/racket/racket/commit/543dab59640fa5e911443baaadaae471406dbf40],
> > which should be fixed in 7.9. - Jon
> > 
> > On Tue, Dec 8, 2020 at 7:19 PM Nathaniel W Griswold
> > <nate@manicmind.earth> wrote:
> >> 
> >> I don’t know if i’m missing something or what, but the following is 
> >> confusing me:
> >> 
> >> (let ([test (mutable-seteqv)])
> >>  (for* ([i (in-range 1000)]
> >>         [j (random 0 1000)])
> >>    (set-add! test j))
> >>  (let ([test-copy (set-copy test)])
> >>    (printf "test-copy=~a\n" (set->list test-copy))
> >>    (printf "Equal from stream is ~a\n" (equal? (list->seteqv (set->list 
> >> test-copy)) test))))
> >> 
> >> prints something like:
> >> test-copy=(31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 
> >> 10 9 8 7 6 5 4 3 2 1 0)
> >> Equal from stream is #f
> >> Equal regular is #t
> >> 
> >> 
> >> Why is this?
> >> 
> >> Thanks
> >> 
> >> Nate
> >> 
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