Sorry for the earlier confusion!

On Tue, Dec 8, 2020 at 6:48 PM Nathaniel W Griswold <nate@manicmind.earth>
wrote:

> Ok. Thanks.
>
> > On Dec 8, 2020, at 6:47 PM, Robby Findler <ro...@cs.northwestern.edu>
> wrote:
> >
> > Right, it is probably both things. I ran your program on yesterday's git
> build and it still returns #false, but for the mutability reason, not the
> bug that Jon mentioned.
> >
> > Robby
> >
> >
> > On Tue, Dec 8, 2020 at 6:45 PM Nathaniel W Griswold <nate@manicmind.earth>
> wrote:
> > I think it is something more. The copied set is giving completely
> different elements. If i loop over the copied set i get 32 values from 0 to
> like 31, when i have in fact added 1000 random elements to the original set
> before copying.
> >
> > Nate
> >
> > > On Dec 8, 2020, at 6:43 PM, Robby Findler <ro...@cs.northwestern.edu>
> wrote:
> > >
> > > No, I don't think that's it. The issue is that one is a mutable set
> and the other isn't, so they aren't equal (even if their elements aren't
> equal).
> > >
> > > > (equal? (mutable-seteqv) (list->seteqv '()))
> > > #f
> > >
> > > Maybe you wanted to call list->mutable-seteqv? Or maybe just start
> with an immutable set?
> > >
> > > Robby
> > >
> > >
> > > On Tue, Dec 8, 2020 at 6:40 PM Nathaniel W Griswold
> <nate@manicmind.earth> wrote:
> > > Thanks. Switching to 7.9 now.
> > >
> > > Nate
> > >
> > > > On Dec 8, 2020, at 6:38 PM, Jon Zeppieri <zeppi...@gmail.com> wrote:
> > > >
> > > > I think that's this bug
> > > > [
> https://github.com/racket/racket/commit/543dab59640fa5e911443baaadaae471406dbf40
> ],
> > > > which should be fixed in 7.9. - Jon
> > > >
> > > > On Tue, Dec 8, 2020 at 7:19 PM Nathaniel W Griswold
> > > > <nate@manicmind.earth> wrote:
> > > >>
> > > >> I don’t know if i’m missing something or what, but the following is
> confusing me:
> > > >>
> > > >> (let ([test (mutable-seteqv)])
> > > >>  (for* ([i (in-range 1000)]
> > > >>         [j (random 0 1000)])
> > > >>    (set-add! test j))
> > > >>  (let ([test-copy (set-copy test)])
> > > >>    (printf "test-copy=~a\n" (set->list test-copy))
> > > >>    (printf "Equal from stream is ~a\n" (equal? (list->seteqv
> (set->list test-copy)) test))))
> > > >>
> > > >> prints something like:
> > > >> test-copy=(31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13
> 12 11 10 9 8 7 6 5 4 3 2 1 0)
> > > >> Equal from stream is #f
> > > >> Equal regular is #t
> > > >>
> > > >>
> > > >> Why is this?
> > > >>
> > > >> Thanks
> > > >>
> > > >> Nate
> > > >>
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