Hello everyone, I am testing my code and find something that I hope someone can conform for me. Thanks in advance. It seems to me that
NumericVector x = as<NumericVector>(x_); ( Btw, this is exactly the same as NumericVector x(x_), both resulting in a shallow copy, isn't it? ) produces a shallow copy, while vector<double> x = as< vector<double> >(x_); produces a deep copy. Is it because for NumvericVector the as() function returns the address of x_? But why does it work differently for vector<double>? Thank you for your answer. Best, Zhongyi
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