Thanks - that does seem to work, but it doesn't perform as well as the pre-copying version.
Here's a Gist so the conversation can be more concrete: https://gist.github.com/kenahoo/4991485 For me, the countSteps() version is about 10 times faster than countSteps2(). -Ken From: John Merrill [mailto:[email protected]] Sent: Tuesday, February 19, 2013 5:46 PM To: Ken Williams Cc: Yan Zhou; Dirk Eddelbuettel; [email protected] Subject: Re: [Rcpp-devel] Efficient DataFrame access by row & column Well, here's a snippet from a much larger routine I used deep inside an implementation of kd-trees: for (int i = 0; i < instances_df.size(); ++i) { const NumericVector& data_column = instances_df[i]; for (int j = 0; j < training_instances.size(); ++j) { // Argument order changes here... instances[j][i] = data_column[training_instances[j]]; } } To set expectations, training_instances can be very large indeed (ca. 1M). The code is quite fast. (And sorry, Dirk -- yes, I really do have an access of the form x[i][j]. Mea culpa, etc.) On Tue, Feb 19, 2013 at 3:26 PM, Ken Williams <[email protected]<mailto:[email protected]>> wrote: > From: John Merrill > [mailto:[email protected]<mailto:[email protected]>] > Sent: Tuesday, February 19, 2013 5:24 PM > To: Ken Williams > Cc: Yan Zhou; Dirk Eddelbuettel; > [email protected]<mailto:[email protected]> > Subject: Re: [Rcpp-devel] Efficient DataFrame access by row & column > > I'm a little puzzled by your question. Could you use a reference instead of > instantiating a new copy? I would love to use a reference, but I don't know how. That's in fact the essence of my question. =) Is there already some example code somewhere showing how to get reference to a DataFrame column without copying? I must be just missing it. -Ken ________________________________ CONFIDENTIALITY NOTICE: This e-mail message is for the sole use of the intended recipient(s) and may contain confidential and privileged information. Any unauthorized review, use, disclosure or distribution of any kind is strictly prohibited. If you are not the intended recipient, please contact the sender via reply e-mail and destroy all copies of the original message. Thank you.
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