Hi there. I tried this code, and it prints one number in the first column, under heading0, and one number under heading1... and that's it.
What am I missing??? Very confused... <smile> Sincerely, > > From: Bill Johnson <[EMAIL PROTECTED]> > Date: 2006/08/14 Mon PM 09:17:13 EST > To: REALbasic NUG <[email protected]> > Subject: Re: my silly listbox > > > On 14-Aug-06, at 5:03 PM, [EMAIL PROTECTED] wrote: > > > > Here is my code.... > > > > after it runs I am left with the number 20 in what I would call > > cell 0,1 > > > > Regards > > > > ======================== > > dim i as integer > > me.HasHeading=true > > > > me.heading(0)="Heading1" > > me.Heading(1)="heading2" > > > > me.addrow"" > > > > for i = 1 to 20 > > me.Cell(0,0)=str(i) > > next i > > The first parameter of the cell property is its row number and the > second is its column number. When you say > > > for i = 1 to 20 > > me.Cell(0,0)=str(i) > > next i > > you're addressing the cell at row 0 and column 0 which is the first > cell in the listbox no matter how many rows you add. > > To fill in the cells of the row you've just added with the cell's > column index increment the column parameter. > dim i as integer > me.HasHeading=true > > me.heading(0)="Heading1" > me.Heading(1)="heading2" > > me.addrow"" > > for i = 0 to 20 > me.Cell(me.lastIndex,i)=str(i) > next > > LastIndex is the index of the last row added to the listbox which is > the one you've just added with me.addrow"". > > Bill Johnson > :::::::: [EMAIL PROTECTED] ::::::: > > > _______________________________________________ > Unsubscribe or switch delivery mode: > <http://www.realsoftware.com/support/listmanager/> > > Search the archives of this list here: > <http://support.realsoftware.com/listarchives/lists.html> > _______________________________________________ Unsubscribe or switch delivery mode: <http://www.realsoftware.com/support/listmanager/> Search the archives of this list here: <http://support.realsoftware.com/listarchives/lists.html>
