Except that the drawing is inclusive of the endpoints; if it
excluded the endpoints (which, if I remember my basic math correctly,
would be expressed as (x1,y1)-(x2,y2), instead of [x1,y1]-[x2,y2],
similar to saying the interval (0,5] excludes 0 but includes 5...)
Besides, while that may be true from a strictly mathematical
perspective (a point has no dimension; no width, no height, no
nuthin!), the poor computer can't draw a pixel that small :)
Otherwise, how would you draw a single point? if you try something
like:
g.DrawLine 0,0,0,1
you'll get a 2-pixel long line starting at 0,0 and ending at 0,1, for
a length of 2; probably not what the user had in mind, methinks...
same if you go from 0,0 to 1,0... :P
Otherwise, DIMming (or REDIMming) an array for 0;
[Re]Dim myArray(0) [As <datatype>] // 'As' part not needed for ReDim
would result in an array with no elements (which is what -1 is for).
Just my 2 red, copper monetary denominations...
Cursors, foiled again! :)
On Oct 13, 2006, at 9:18 AM, [EMAIL PROTECTED] wrote:
On Oct 13, 2006, at 12:55 UTC, Richard wrote:
In the method:
Graphics.DrawLine(x1,y1,x2,y2)
If x1=x2 and y1=y2, there is no line drawn. Yes, it's only 1 pixel
but I would expect a 1-pixel line.
I wouldn't; the length of this line is x2-x1=0, and the height is
y2-y1=0. That's not a 1-pixel line, that's a 0-pixel line. Correct
behavior would be to draw nothing. (Though I can imagine poorly
thought-out systems that would actually draw a pixel under these
circumstances, I would consider such a system to be flawed.)
Any suggestions?
Yes: don't do that. :)
Best,
- Joe
--
Joe Strout -- [EMAIL PROTECTED]
Verified Express, LLC "Making the Internet a Better Place"
http://www.verex.com/
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