Hi Sunanda: >If you are going to use set, you could use a shorter method: > > set [foo bar baz] copy [] > You will find that only foo is set set to a block, whereas bar and baz are initialized to the value none. This is unlike using set [foo bar baz[] 3 ;- (i.e. some non-series value where all words will be initialized to the same value.
> >Another method you will see around is: > > foo: bar: baz: copy [] > Note that, unlike in Greg's example, here all three words will be set to one and the same block. I.e. any modifications made to the block baz will also affect the blocks foo and bar, because they are one and the same block. -- To unsubscribe from this list, just send an email to [EMAIL PROTECTED] with unsubscribe as the subject.
